Knowledge Chemical Engineering Education How is the ideal gas constant R converted between SI and American units? Ensure accurate pilot-plant models
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Tech Team · LABPARK

Updated 2 months ago

How is the ideal gas constant R converted between SI and American units? Ensure accurate pilot-plant models


The ideal gas constant converts to approximately 0.7302 atm·ft³/(lb-mol·°R) in American Engineering units. Starting from (R = 8.314\ \text{kPa·m}^3/(\text{kmol·K})), convert pressure, volume, amount of substance, and absolute temperature consistently. The equivalent pressure-volume form commonly used in US chemical engineering calculations is (R = 10.7316\ \text{ft}^3\text{·psia}/(\text{lb-mol·°R})).

The numerical value of (R) is not universal across unit expressions. Its physical meaning is unchanged, but its numerical value changes with the selected pressure, volume, molar-quantity, and temperature units.

Converting (R) from SI to American Engineering Units

Starting SI expression

For pilot-plant gas calculations, a convenient SI form is:

[ R = 8.314\ \frac{\text{kPa·m}^3}{\text{kmol·K}} ]

Here, (\text{kmol}) and (\text{kgmol}) are equivalent quantity units. The same constant can also be written as:

[ R = 8.314\ \frac{\text{J}}{\text{mol·K}} ]

because (1\ \text{kPa·m}^3 = 1\ \text{kJ}) and (1\ \text{kmol} = 1000\ \text{mol}).

Required conversion factors

Use the following relationships:

[ 1\ \text{atm} = 101.325\ \text{kPa} ]

[ 1\ \text{m}^3 = 35.3147\ \text{ft}^3 ]

[ 1\ \text{kmol} = 2.20462\ \text{lb-mol} ]

[ 1\ \text{K} = 1.8\ ^\circ\text{R} ]

For absolute temperatures, the corresponding operating-temperature conversion is:

[ T_{^\circ R} = 1.8T_K ]

Step-by-step conversion

The conversion is:

[ R = 8.314 \left(\frac{1\ \text{atm}}{101.325\ \text{kPa}}\right) \left(\frac{35.3147\ \text{ft}^3}{1\ \text{m}^3}\right) \left(\frac{1\ \text{kmol}}{2.20462\ \text{lb-mol}}\right) \left(\frac{1\ \text{K}}{1.8\ ^\circ\text{R}}\right) ]

Therefore:

[ \boxed{ R = 0.7302\ \frac{\text{atm·ft}^3}{\text{lb-mol·}^\circ\text{R}} } ]

The temperature factor appears as division by (1.8) because the reciprocal temperature unit changes from (\text{K}^{-1}) to ((^\circ\text{R})^{-1}).

Selecting the Correct Form of (R)

For pressure in atmospheres

Use:

[ \boxed{ R = 0.7302\ \frac{\text{atm·ft}^3}{\text{lb-mol·}^\circ\text{R}} } ]

The ideal gas law becomes:

[ PV=nRT ]

with (P) in atm, (V) in ft³, (n) in lb-mol, and (T) in °R.

For pressure in psia

Pilot plants and industrial instruments often report absolute pressure in psia. In that case, use:

[ \boxed{ R = 10.7316\ \frac{\text{psia·ft}^3}{\text{lb-mol·}^\circ\text{R}} } ]

This value follows from:

[ 10.7316 = 0.7302 \times 14.696 ]

where (14.696\ \text{psia}) is approximately one standard atmosphere.

For SI calculations

Use one of these equivalent forms:

[ R = 8.314\ \frac{\text{J}}{\text{mol·K}} ]

[ R = 8.314\ \frac{\text{kPa·m}^3}{\text{kmol·K}} ]

[ R = 8.314\ \frac{\text{kPa·dm}^3}{\text{mol·K}} ]

The last form is useful because (1\ \text{kPa·dm}^3 = 1\ \text{J}).

Applying the Conversion in Pilot-Plant Models

Gas volume and molar flow

For a gas stream measured in American Engineering units:

[ \dot V = \frac{\dot nRT}{P} ]

Use (R=10.7316\ \text{psia·ft}^3/(\text{lb-mol·°R})) when pressure is in psia and the resulting volumetric flow is required in ft³ per unit time.

Absolute pressure is essential. A gauge-pressure reading must be converted before use:

[ P_{\text{absolute}}=P_{\text{gauge}}+P_{\text{atmospheric}} ]

Gas-phase component concentration

For component (A) in a mixture:

[ C_A=\frac{P_A}{RT}=\frac{y_A P}{RT} ]

where (y_A) is the mole fraction and (P_A) is the partial pressure. With (P) in psia, (T) in °R, and the US customary form of (R), (C_A) is obtained in lb-mol/ft³.

This relationship is directly useful for absorption, stripping, distillation, and gas-phase reactor calculations.

Temperature conversion

Temperature must be absolute, not gauge-based or relative. The relevant conversions are:

[ T_K = t_{^\circ C}+273.15 ]

[ T_{^\circ R}=t_{^\circ F}+459.67 ]

Using °F or °C directly in (PV=nRT) produces an incorrect result because those scales do not begin at absolute zero.

Understanding the Trade-offs

Unit consistency is more important than the chosen system

SI and American Engineering units are both valid for pilot-plant modeling. The calculation fails when pressure, volume, molar quantity, temperature, and (R) are mixed across systems.

A common error is using (R=0.7302) with pressure in psia. That combination is invalid because (0.7302) is based on atm, whereas psia calculations require (R=10.7316).

Ideal-gas behavior has operating limits

The ideal gas law is generally reliable for many gases at low to moderate pressures and ambient or elevated temperatures. Under these conditions, intermolecular forces and molecular volume have relatively small effects.

At high pressure, near condensation, or at low temperature, real-gas behavior can become significant. Carbon dioxide, ammonia, and light hydrocarbon vapors may require particular caution because non-ideal effects can appear earlier than for simpler gases.

Instrument calibration does not replace unit verification

A pressure transmitter may report psig, psia, kPa, or bar, while a flow controller may use standard or actual volumetric flow. These distinctions must be identified before applying (PV=nRT).

Standard volumetric flow also requires a stated reference pressure and temperature. It cannot be substituted directly for actual operating volume without a defined conversion.

Making the Right Choice for Your Goal

Use the value of (R) that matches every variable in the governing equation.

  • If your primary focus is SI-based mass and energy balances: Use (R=8.314\ \text{J}/(\text{mol·K})) or (8.314\ \text{kPa·m}^3/(\text{kmol·K})), with pressure in Pa or kPa and temperature in K.
  • If your primary focus is atmospheric-pressure US calculations: Use (R=0.7302\ \text{atm·ft}^3/(\text{lb-mol·°R})), with pressure in atm and temperature in °R.
  • If your primary focus is industrial pressure and flow instrumentation: Use (R=10.7316\ \text{psia·ft}^3/(\text{lb-mol·°R})), and convert gauge pressure to absolute pressure.
  • If your primary focus is gas absorption or reaction-rate modeling: Use (C_A=y_AP/(RT)) and confirm that the resulting concentration units match the mass-transfer or kinetic correlation.

Reliable pilot-plant modeling depends less on choosing SI or American Engineering units than on maintaining absolute temperature, absolute pressure, and complete unit consistency throughout the calculation.

Summary Table:

Calculation need Recommended R Required units
SI gas calculations 8.314 J/(mol·K) Pressure in Pa, volume in m³, temperature in K
SI kmol calculations 8.314 kPa·m³/(kmol·K) Pressure in kPa, volume in m³, temperature in K
Atmospheric-pressure US calculations 0.7302 atm·ft³/(lb-mol·°R) Pressure in atm, volume in ft³, temperature in °R
Industrial US instrumentation 10.7316 psia·ft³/(lb-mol·°R) Absolute pressure in psia, volume in ft³, temperature in °R
Gas concentration Cₐ = yₐP/(RT) Confirm concentration units match the model or correlation
Essential checks Use absolute P and T Convert psig to psia and °F to °R before calculation

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